Find the center, vertices, and foci of the ellipse with equation 5x2 + 8y2 = 40.

For an ellipse x²/a² + y²/a² = 1

vertices are -a,0 a, 0 0, b 0, b focus : √(a²-b²), 0**center is origin 0,0****given ellipse : divide by 40 on both sides****x² / 8 + y²/5 = 1****So a = √8 = 2√2 b = √5 ****vertices are -2√2,0 2√2,0 0,√5 0,√5****focii = √3, 0 -√3, 0**

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