Find the center, vertices, and foci of the ellipse with equation 5x2 + 8y2 = 40.

For an ellipse  x²/a²  +  y²/a²  = 1 
vertices are  -a,0      a, 0            0, b     0, b      focus : √(a²-b²), 0
center is origin 0,0

given ellipse     : divide by 40 on both sides

x² / 8  + y²/5  = 1
So a = √8 = 2√2            b = √5 
vertices are -2√2,0      2√2,0        0,√5    0,√5
focii  =  √3, 0    -√3, 0


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