3. Factor.

9*x*2 + 15*x*

(Points : 1) *x*(3*x* + 5)

3*x*(3*x* + 5)

9*x*(*x* + 5)

3*x*2(3*x* + 5)

20

*mn*− 30

*m*

(Points : 1) 2

*m*− 3

10

*m*(2

*n*− 3)

10

*mn*(2

*m*+ 3

*n*)

10

*n*(2

*m*− 3) Question 5.5. Factor.

8

*x*2

*y*2 − 4

*x*2

*y*− 12

*xy*

(Points : 1) 4(2

*xy*− 4

*x*2

*y*− 12

*xy*)

4(8

*x*2

*y*2 −

*x*− 12

*xy*)

4

*x*2

*y*2(2

*xy*−

*xy*−3)

4

*xy*(2

*xy*−

*x*− 3)

It seems that some the work is already here, but I’d be glad to! So for #3 which is 9x^2+15x, we can factor out both a 3 and an x (3x) so we know that 3x * 3x =9x^2 and 3x * 5 = 15x so once we take the 3x out of the equation, we are left with 3x(3x+5) and that’s as far as you can factor.

For #4, we see that the common factor is 10m because 10m * 2n = 20mn and 10m * 3 = 30m so once we take 10m out of the original, it becomes 10m(2n-3)

For #5, this one the common factor is 4xy because 4xy * 2xy=8x^2y^2 and 4xy*x= 4x^2y and 4xy*3=12xy so once we take the 4xy out of the equation, it becomes 4xy(2xy-x-3)

!

RELATED: