To solve this problem we simply need to find the lengths of each side of the triangle. To do this, we use the distance formula: √(x1-x2)^2+(y1-y2)^2. Using points J and K, we find that the length of JK is √(3-4)^2+(-1-(-4))^2=√(-1)^2+(3)^2=√1+9=√10. Then we do the same for JL and KL. JL is √(3-1)^2+(-1-(-3))^2=√(2)^2+(2)^2=√4+4=√8. KL is √(4-1)^2+(-4-(-3)^2)=√(3)^2+(-1)^2=√9+1=√10. Now we have all three sides of the triangle: √10, √8, and √10. Check for any similarities: you have two sides of √10. Because there are two sides of the triangle of the same length, the triangle is an isosceles triangle.

Quadrilateral 2004-06-02-01-00_files/i0230001. jpg is a rectangle with vertices D(–8, 2), E(2, 7), F(5, 1), and G(–5, –4). Find the area of the rectangle.

A.

60 u2

B.

75 u2

C.

112 u2

D.

150 u2