Parallel lines are cut by a transversal such that the alternate interior angles have measures of 3x + 17 and x + 53 degrees. The value of x is

9

18

35

71

9

18

35

71

When parallel lines are cut by a transversal, the alternate interior angles are equal.

3x + 17 = x + 53

Subtract ’x’ from each side:

2x + 17 = 53

Subtract 17 from each side:

2x = 36

Divide each side by 2 :**x = 18**

Well the sum of the alternate interior angles of a transversal cutting parallel lines should be equal to 180’.

So (3x+17)=(x+53)

3x+17=x+53

Using transposition method-

3x-x=53-17

2x=36

x=36/2

x=18

Hopw i helped!

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