Find the just common denominator $$\frac{4}{6}$$ + $$\frac{2}{3}$$

$$\frac{4}{6}$$ + $$\frac{2}{3}$$
First, simplify $$\frac{4}{6}$$ to $$\frac{2}{3}$$ / Your problem should look like: $$\frac{2}{3}$$ + $$\frac{2}{3}$$
Second, join the denominators. / Your problem should look like: $$\frac{2+2}{3}$$
Third, simplify. / Your problem should look like: $$\frac{4}{3}$$
Fourth, convert to mixed fraction. / Your problem should look like: $$1\frac{1}{3}$$

Mixed number form: $$1\frac{1}{3}$$
Exact form: $$\frac{4}{3}$$

$$\frac{4}{6} + \frac{2}{3}$$ =?

You need to find a common denominator to add them which is 6

6×1=6 and 3×2=6

What you do on the denominator, you must do in the numerator

$$\frac{4}{6} + \frac{4}{5}$$ = $$\frac{8}{6}$$

To reduce, find a common factor which in this case is 2

8÷2=4 and 6÷2=3 ⇒ $$\frac{4}{3}$$

To change to a mix fraction, divide the numerator by the denominator

$$\frac{4}{3}$$ ⇒ $$1 \frac{1}{3}$$
Answer: $$\frac{4}{3}$$ as an improper fraction or $$1 \frac{1}{3}$$ as a mixed fraction

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