solve quadratic formula

x-2x-15=0

the first x is squared

\( x^2-2x-15=0\\ x^2-5x+3x-15=0\\ x(x-5)+3(x-5)=0\\ (x+3)(x-5)=0\\ x=-3 \vee x=5 \)

You said that x² - 2x - 15 = 0.

You could factor the left side:

(x + 3) (x - 5) = 0

This equation is true if either of the factors is zero. **First factor:**

x + 3 = 0**x = -3****Second factor:**

x - 5 = 0**x = 5**

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