Graph the line using intercepts: 4x-3y=12

First you have to find the intercepts!

To find the y-intercept (I usually do that first), pretend x=0.
Then it becomes:
4(0)-3y=12
Which then becomes:
-3y=12.
Divide both sides, and y = -4.
Then the (x, y) coordinate would become (0,4).

Next you would find the x-intercept, and pretend y = 0.
Which then becomes:
4x-3(0)=12
3x0 cancels out to become:
4x = 12
And x = 3 because division stuffs.
Then THIS point would then be (3,0).

So then, you would plot (0,4) and (3,0) on a graph and connect the points! I attached a picture for reference.

Graph the intercepts by assigning the balue to y or x then after u assign u will graph it. Since it is a linear equation it might be easier so it may be a  line not a parabola


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