Write a system of equations with a solution (4,–3)

1. So we have the system of equation. (4,3)

let’s create another system of equation.

Let a = 4

and Let b = -3

First equation

=> Let’s pick any numbers to be used. Let’s have number 5

=> 5a + 5b

=> 5 (4) + 5 (-3)

=> 20 + (-15)

negative and positive is equals to negative

=> 20 – 15

=> 5 (this the first value of our equation, let this be the value of X)

Second

=> Pick another number, Let’s have 6

=> 6a + 6b

=> 6 (4) + 6 (-3)

=> 24 + (-18)

=> 24 – 18

=> 6 (this is the value of our second equation, let this value be Y)

Now, we have (A, B) = (4,3) and (X, Y) = (5,6)

RELATED: