A man invested a total of $3,000 in two investments. he made a profit of 3% on the first investment and 4% on the second investment. if his total profit was $107, what was the amount of each investment?

Let the amount that the man placed in the first investment be \( x \). Then, the amount that he placed in the second investment has to be \( \$3000 - x \). Using those as the investment amounts, the total profit is given by adding the two separate profits as shown:

\(.03x +.04(\$3000 - x) = \$107 \)

We can now solve for x:

\(.03x +.04(\$3000 - x) = \$107 \)
\(.03x + (\$120 -04x) = \$107 \)
\( \$120 -01x = \$107 \)
\(.01x = \$13 \)
\( x = \$1300 \)

Thus,

First investment: \( x = \bf \$1300 \)
Second investment: \( \$3000 - x = \$3000 - \$1300 = \bf \$1700 \)


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