A man invested a total of $3,000 in two investments. he made a profit of 3% on the first investment and 4% on the second investment. if his total profit was$107, what was the amount of each investment?

Let the amount that the man placed in the first investment be $$x$$. Then, the amount that he placed in the second investment has to be $$\3000 - x$$. Using those as the investment amounts, the total profit is given by adding the two separate profits as shown:

$$.03x +.04(\3000 - x) = \107$$

We can now solve for x:

$$.03x +.04(\3000 - x) = \107$$
$$.03x + (\120 -04x) = \107$$
$$\120 -01x = \107$$
$$.01x = \13$$
$$x = \1300$$

Thus,

First investment: $$x = \bf \1300$$
Second investment: $$\3000 - x = \3000 - \1300 = \bf \1700$$

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