Use the functions f(x) = 3x – 4 and g(x) = x2 – 2 to answer the following questions. Complete the tables.


x f(x)–3–1 0 2 5

x g(x)–3–1 0 2 5

For what value of the what value of the domain {–3, –1, 0, 2, 5} does f(x) = g(x) {–3, –1, 0, 2, 5} does f(x) = g(x)? Answer:
















consider the relation {(–4, 3), (–1, 0), (0, –2), (2, 1), (4, 3)}. Graph the relation.
State the domain of the relation. State the range of the relation. Is the relation a function? know? Answer:











2. graph the function f(x) = |x + 2|.


Answer:






consider the following expression. Rewrite the expression so that the first denominator is in factored form. Determine the LCD. (Write it in factored form. ) Rewrite the expression so that both fractions are written with the LCD. Subtract and simplify.

Answer:

\( 1)\\f(x)=3x-4\\|\ \ \ x\ \ \ |\ \ -3\ \ \ |\ \ -1\ \ \ |\ \ \ 0\ \ \ |\ \ \ 2\ \ \ |\ \ \ 5\ \ \ |\\=========================\\|\ f(x)\ |\ \ -13\ \ |\ \ -7\ \ |\ -4\ \ |\ \ \ 2\ \ \ |\ \ \ 11\ \ |\\\\f(-3)=3\cdot(-3)-4=-9-4=-13\\f(-1)=3\cdot(-1)-4=-3-4=-7\\f(0)=3\cdot0-4=0-4=-4\\f(2)=3\cdot2-4=6-4=2\\f(5)=3\cdot5-4=15-4=11 \)

\( g(x)=x^2-2\\|\ \ \ x\ \ \ |\ \ -3\ \ \ |\ \ -1\ \ \ |\ \ \ 0\ \ \ |\ \ \ 2\ \ \ |\ \ \ 5\ \ \ |\\=========================\\|\ g(x)\ |\ \ \ \ \ 7\ \ \ \ |\ \ -1\ \ \ |\ -2\ \ |\ \ \ 2\ \ |\ \ \ 23\ \ |\\\\g(-3)=(-3)^2-2=9-2=7\\g(-1)=(-1)^2-2=1-2=-1\\g(0)=0^2-2=0-2=-2\\g(2)=2^2-2=4-2=2\\g(5)=5^2-2=25-2=23\\\\f(x)=g(x)\ \ \ \Leftrightarrow\ \ \ x=2,\ \ \ \ because\ \ \ \ f(2)=2\ \ \ and\ \ \ g(2)=2 \)

\( 2)\\the\ relation:\ \{(-4, 3), (-1, 0), (0,2), (2,1), (4, 3)\}.\\\\the\ domain:\ D=\{-4,1,0,2,4\}\\the\ range:\ R=\{3,0,2,1\}\\\\This\ relation\ is\ the\ function,\ because\ \ each\ number\\ of\ the\ domain\ D\ has\ exactly\ one\ value\ in\ the\ range\ R. \)

\( 3) f(x)=|x+2|\\\\|x+2|= \left \{{x+2\ \ \ \ \ if\ \ \ x \geq -2} \atop {-x-2\ \ \ if\ \ \ x<-2} \right. \)


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