Jon is standing on a bridge over a creek. He releases a stone 20 feet from the water. How long will it take the stone to hit the water?

The distance covered by a free-falling object in ’T’ seconds after it’s dropped is

D = (1/2) x (gravity acceleration) x (T²)

Gravity acceleration on Earth is 9.8 m/s². or 32.2 feet/sec².

20-ft = (1/2) (16.1) (T²)

20 = 8.05 T²

T = √(20/8.05) = **1.576 seconds. **

No. I screwed up. 20 = (1/2)(32.2)(T-sqrd). / / / 20 = 16.1 T-sqrd. T= sqrt of (20/16.1) = 1.115 seconds. Forgive me.

could you please help with a problem, Jon takes a stone and tosses it straight up with a velocity of 30 feet per second. how long will it take this stone to hit the water?

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