Book a has 24 more pages than book b. book c has 4 times as many pages as book a. the total number of pages of the three books is 180. how many pages does book b have?

A=24+b
c=4a
c=4(24+b)
a+b+c=180
24+b+b+4(24+b)=180
24+b+b+96+4b=180
120+6b=180
6b=60
b=10
a=24+10
a=34
c=4(34)
c=136
34+10+136=180
So book a has 34 pages, book b has 10 pages, and book c has 136 pages.

a=b+24
c=4a
b=a-24
a+b+c=180
sub in a, b and c into a+b+c=180
b+24+4a+a-24=180
b+5a=180
sub a=b+24
b+5(b+24)=180
b+5b+120=180
6b=180-120
6b=60
b=10
Book B has 10 pages

a=24+b A is 24
c=4a
c=4(24+b)
a+b+c=180
24+b+b+4(24+b)=180
24+b+b+96+4b=180
120+6b=180
6b=60
b=10
a=24+10
a=34
c=4(34)
c=136
34+10+136=180
So book a has 34 pages, book b has 10 pages, and book c has 136 pages.

a=24+b A is 24+b because it has 24 more pages than book b
c=4a C is 4a because it has 4 times as many pages as book a
c=4(24+b) Since C is 4a and A is 24+b, you can substitute a into 4a which gives you 4(24+b(
a+b+c=180 the total number of all three books is 180 so a +b+c=180
24+b+b+4(24+b)=180
24+b+b+96+4b=180
120+6b=180
6b=60
b=10
a=24+10
a=34
c=4(34)
c=136
34+10+136=180
So book a has 34 pages, book b has 10 pages, and book c has 136 pages.

a=24+b
c=4a
c=4(24+b)
a+b+c=180
24+b+b+4(24+b)=180 you substitute what each variable equals into the equation. a is 24+b so you have 24+b+b+c=180. then c equals 4(24+b) because it is 4 times as many pages as book a so then you have 24+b+b+4(24+b)=180
24+b+b+96+4b=180 then you start simplifying the equation. you start with the distributive property
120+6b=180
6b=60
b=10
a=24+10
a=34
c=4(34)
c=136
34+10+136=180
So book a has 34 pages, book b has 10 pages, and book c has 136 pages.

a=24+b
c=4a
c=4(24+b)
a+b+c=180
24+b+b+4(24+b)=180
24+b+b+96+4b=180 once distribute 4(24+b) you have 96+4b
120+6b=180
6b=60
b=10
a=24+10
a=34
c=4(34)
c=136
34+10+136=180
So book a has 34 pages, book b has 10 pages, and book c has 136 pages.

a=24+b
c=4a
c=4(24+b)
a+b+c=180
24+b+b+4(24+b)=180
24+b+b+96+4b=180
120+6b=180 then you combine like terms. 24 and 96 can be added together to get 120. b and b and 4b can be added together to get 6b. so then you have 6b+120=180
6b=60 subtract 120 from both sides to isolate the variable b.
b=10 then you divide each side by 6 to further isolate the variable b.
a=24+10
a=34
c=4(34)
c=136
34+10+136=180
So book a has 34 pages, book b has 10 pages, and book c has 136 pages.

a=24+b
c=4a
c=4(24+b)
a+b+c=180
24+b+b+4(24+b)=180
24+b+b+96+4b=180
120+6b=180
6b=60
b=10 once you know that b equals 10, you can substitute into the other equations to find out how many pages the other books have.
a=24+10 a originally equalled 24+b but since we know that b is 10, we can substitute 10 into the equation to find that 24+10=34
a=34
c=4(34)
c=136
34+10+136=180
So book a has 34 pages, book b has 10 pages, and book c has 136 pages.

a=24+b
c=4a
c=4(24+b)
a+b+c=180
24+b+b+4(24+b)=180
24+b+b+96+4b=180
120+6b=180
6b=60
b=10
a=24+10
a=34
c=4(34) c originally equaled 4a but now that we know that a is 34, we can substitute into the equation to find that 4(34) is 136 which is c.
c=136
34+10+136=180 to prove that your work is right, substitute the values into a+b+c=180. once you add them, you find that they add up to 180 and therefore youre right
So book a has 34 pages, book b has 10 pages, and book c has 136 pages.

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