please show the work

A=24+b

c=4a

c=4(24+b)

a+b+c=180

24+b+b+4(24+b)=180

24+b+b+96+4b=180

120+6b=180

6b=60

b=10

a=24+10

a=34

c=4(34)

c=136

34+10+136=180

So book a has 34 pages, book b has 10 pages, and book c has 136 pages.

**a=b+24****c=4a****b=a-24****a+b+c=180****sub in a, b and c into a+b+c=180**

b+24+4a+a-24=180

b+5a=180

sub a=b+24

b+5(b+24)=180

b+5b+120=180

6b=180-120

6b=60

b=10**Book B has 10 pages**

a=24+b A is 24

c=4a

c=4(24+b)

a+b+c=180

24+b+b+4(24+b)=180

24+b+b+96+4b=180

120+6b=180

6b=60

b=10

a=24+10

a=34

c=4(34)

c=136

34+10+136=180

So book a has 34 pages, book b has 10 pages, and book c has 136 pages.a=24+b A is 24+b because it has 24 more pages than book b

c=4a C is 4a because it has 4 times as many pages as book a

c=4(24+b) Since C is 4a and A is 24+b, you can substitute a into 4a which gives you 4(24+b(

a+b+c=180 the total number of all three books is 180 so a +b+c=180

24+b+b+4(24+b)=180

24+b+b+96+4b=180

120+6b=180

6b=60

b=10

a=24+10

a=34

c=4(34)

c=136

34+10+136=180

So book a has 34 pages, book b has 10 pages, and book c has 136 pages.a=24+b

c=4a

c=4(24+b)

a+b+c=180

24+b+b+4(24+b)=180 you substitute what each variable equals into the equation. a is 24+b so you have 24+b+b+c=180. then c equals 4(24+b) because it is 4 times as many pages as book a so then you have 24+b+b+4(24+b)=180

24+b+b+96+4b=180 then you start simplifying the equation. you start with the distributive property

120+6b=180

6b=60

b=10

a=24+10

a=34

c=4(34)

c=136

34+10+136=180

So book a has 34 pages, book b has 10 pages, and book c has 136 pages.a=24+b

c=4a

c=4(24+b)

a+b+c=180

24+b+b+4(24+b)=180

24+b+b+96+4b=180 once distribute 4(24+b) you have 96+4b

120+6b=180

6b=60

b=10

a=24+10

a=34

c=4(34)

c=136

34+10+136=180

So book a has 34 pages, book b has 10 pages, and book c has 136 pages.a=24+b

c=4a

c=4(24+b)

a+b+c=180

24+b+b+4(24+b)=180

24+b+b+96+4b=180

120+6b=180 then you combine like terms. 24 and 96 can be added together to get 120. b and b and 4b can be added together to get 6b. so then you have 6b+120=180

6b=60 subtract 120 from both sides to isolate the variable b.

b=10 then you divide each side by 6 to further isolate the variable b.

a=24+10

a=34

c=4(34)

c=136

34+10+136=180

So book a has 34 pages, book b has 10 pages, and book c has 136 pages.a=24+b

c=4a

c=4(24+b)

a+b+c=180

24+b+b+4(24+b)=180

24+b+b+96+4b=180

120+6b=180

6b=60

b=10 once you know that b equals 10, you can substitute into the other equations to find out how many pages the other books have.

a=24+10 a originally equalled 24+b but since we know that b is 10, we can substitute 10 into the equation to find that 24+10=34

a=34

c=4(34)

c=136

34+10+136=180

So book a has 34 pages, book b has 10 pages, and book c has 136 pages.a=24+b

c=4a

c=4(24+b)

a+b+c=180

24+b+b+4(24+b)=180

24+b+b+96+4b=180

120+6b=180

6b=60

b=10

a=24+10

a=34

c=4(34) c originally equaled 4a but now that we know that a is 34, we can substitute into the equation to find that 4(34) is 136 which is c.

c=136

34+10+136=180 to prove that your work is right, substitute the values into a+b+c=180. once you add them, you find that they add up to 180 and therefore youre right

So book a has 34 pages, book b has 10 pages, and book c has 136 pages.