A tank of water holding 528 kl of water begain to empty at a rate of 10 kl/min at the same time a another tank whitch is empty begins to fill at a rate of 14kl/min let k repreasens the number of kiloliters of water and let t repreasent time in min the system models the solution

How long will it take for each tank to have the Same amount of water, and how much water will that be

It will take __minitutes for both tanks to hold equal amounts of water. They will each hold ___ kiloliters.

This is a system of equations.  The first equation represents the tank being emptied and the second equation represents the tank being filled:

k = -10t + 528
k = 14t

To solve this system of equations, we will use substitution. The second equation says that k is equal to 14t, so we can substitute 14t for k in the first equation.

14t = -10t + 528
24t = 528
t = 22

Now that we have t, we can use it to find k by plugging it in to the second equation:

k = 14(22)
k = 308

So, it will take 22 minutes for both tanks to hold equal amounts of water. They will each hold 308 kiloliters.

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