\( \bf \qquad \textit{degree of a polynomial} \\\\ x^2+3x+1\impliedby \begin{array}{llll} ^2\textit{highest exponential sum}\\ \textit{thus is a 2nd degree}\\ \end{array} \)

\( \bf 3x+y^{11}x-z^5v^8x^2\impliedby \begin{array}{llll} \textit{now, the degree of this polynomial}\\ \textit{3x has an x with exponent of one, but}\\ \textit{2nd term has y with 11 and x with 1}\\ \textit{11 + 1 = 12, 2nd term has degree of 12}\\ \textit{now, the last term}\\ \textit{has a degree of 5+8+2=15}\\ \textit{15 is bigger than 12, thus, the degree}\\ \textit{of this polynomial is 15} \end{array} \)

now, let’s take a peek at your expression

\( \bf 5x^{?}y^3+xy^2+8\implies \begin{cases} x^{?}y^3\leftarrow \textit{degree is?+3}\\ x^1y^2\leftarrow \textit{degree is 1+2=3}\\ 8\leftarrow \textit{degree is 0, no variable} \end{cases} \)

so. what do you think "x" is missing on the first term, to make the whole polynomial of 5th degree?

2 is the correct answer