Graph the system of ineqalities

y<2x+2

y>-x-1

y<2x+2

y>-x-1

To graph the system of inequalities you have to **start with drawing both lines:**

1) y=2x+2: this one is crossing points: (0,2) and (-1,0)

2) y=-x-1: this one is crossing: (0,1) and (-1,0)

When you have it done you have to identify the area (set of points)** that satisfies both inequalities**. In the first case: y<2x+2, these gonna be all points below this line excluding the line (because the sign is "<"). In the second case: y>-x-1, the area includes all the points above this line including the line (because the sign is ">").

The result is a common set of the areas: x>-1 and -x-1< y<2x+2.

Please find the graph attached!

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