how do you solve the system of elimination method.
x6y=30
2x5y=25
X6y=30. equatn 1
2x5y=25. equatn 2
multiply eqn 1 and 2 with 5 and 6 respectively
5x30y=150
12x30y=150
subtract to eliminate y
17x=0
x=0
substitute x=0 into any of the equations
06y=30
6y=30
y=30/6
y=5
x=0; y=5
X  6y = 30 / * 2
2x  5y = 25
2x  12y = 60
2x  5y = 25

+
2x  2x  12y  5y = 60  25
17y = 85 / : (17)
y = 85/17
y = 5
y = 5
x  6y = 30
y = 5
x  6 * 5 = 30
y = 5
x  30 = 30
y = 5
x = 30  30
y = 5
x = 0
answer:
x = 0
y = 5
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