IMPOSSIBLE MATH QUESTION
(1+tan (1))(1+tan (2))(1+tan (3))(1+tan (4)).(1+tan (45))=?
find the value

Well u can also do this without a calculator
take \( tan 1=tan(45-44)=\frac{1-tan44}{1+tan 44} \) 
then 
\( (1+tan1)=(1+ \frac{1-tan44}{1+tan 44})=\frac{2}{1+tan 44} \)
therefore similarly
\( (1+tan 1)(1+tan 2).(1+tan 22)= \frac{2}{1+tan 44} \frac{2}{1+tan 43}\frac{2}{1+tan 42}.\frac{2}{1+tan 23} \)
\( = \frac{2^{22}}{(1+tan 44)(1+tan 43)(1+tan 42).(1+tan 23)} \)
then \( (1+tan 1).(1+tan 45)= \frac{2^{22}}{(1+tan 44)(1+tan 43)(1+tan 42).(1+tan 23)}(1+tan 23)(1+tan 24).(1+tan 45) \)
\( =2^{22}(1+tan45)=2^{23}=8388608 \)

(1+tan 1)(1+ tan 2).(1+tan 45)=(1+0.017455)(1+0.03492).(1+1)=8388608.11


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