You can answer this by using Pythagoras theorem. Okay, let me draw this first.

2 miles

V

________________________

| |

| |

| | << 1.5 miles

|_______________________|

^ Assume this is the rectangle. The long side is 2 miles while the shorter side is 1.5 miles.

So, to get the shortest distance, let’s cut out a triangle from the rectangle.

/|

/ |

/ |

What we want to find is this one > / | << 2 miles

/ |

/______|

^ 1.5 miles (I know the size is not logical, but imagine it please)

So to get the diagonal length = \( \sqrt{{a^{2} }+ b^{2}} \)

= \( \sqrt{{2^{2} }+ 1.5^{2}} \)

= 2.5 miles

To calculate how much shorter = ( 2 miles + 1.5 miles) - 2.5 miles

= 3.5 miles - 2.5 miles

= 1.0 miles

A park is in the shape of a rectangle 2 miles long and 1.5 miles wide. How much shorter if you walk diaganolly across the park rather than along two sides?

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