ok so remember that

\( \frac{x+y}{y} + \frac{z}{y} +\frac{x}{y} \)

and

\( \frac{x}{x}=1 \)

we normally split it up into a mixed fractio (examle, 3/2=1 and 1/2)

so find how many 99’s are in 1345 (find 1’s and simplify using first thing)

99 is like 100 so

how many 100’s fit in 1345

aprox 13

so 99 times 13=99 times (10+3)=990+300-3=1287

so 13 ones=1287/99

so nowe we find the remainder

1345-1287=58

so

\( \frac{1345}{99}=\frac{1287}{99}+ \frac{58}{99}=13+\frac{58}{99} \)

so we round \( \frac{58/99} \) to nearest integer (counting number)

we see if 58/99 is more than 1/2 or less

99 is like 100

100’s half way point=50

58>50 by alot so therefor 58/99>1/2 so round up

13+1=14

answer is 14

Your a life saver, i had to go over your explanation about 4 or 5 times before i i finally understood but still thnx man